Consider the following reaction
$(a)\, B_2H_6 + 6H_2O \to$
$(b)\, B_2H_6 + 6CH_3OH \to$
$(c)\, B_2H_6 + 3Cl_2 \to$
$(d)\, BR_3 + 3CH_3COOH \to$
Identify incorrect statement about product $(s)$
Consider the following reaction
$(a)\, B_2H_6 + 6H_2O \to$
$(b)\, B_2H_6 + 6CH_3OH \to$
$(c)\, B_2H_6 + 3Cl_2 \to$
$(d)\, BR_3 + 3CH_3COOH \to$
Identify incorrect statement about product $(s)$
- A
$H_2$ is common product in all the reactions
- B
Reaction $(d)$ forms alkane
- C
Product of reaction $(a)$ has $H-$ bond in solid state
- D
one of the product of reaction $(c)$ is used for dissolving noble metals along with $HNO_3$ (conc.)
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In $B_2H_6$
In $B_2H_6$
The bond dissociation energy of $B- F$ in $BF_3$ is $646 \,kJ\, mol^{-1}$ whereas that of $C - F$ in $CF_4$ is $515\, kJ\, mol^{-1}.$ The correct reason for higher $B- F$ bond dissociation energy as compared to that of $C-F$ is
The bond dissociation energy of $B- F$ in $BF_3$ is $646 \,kJ\, mol^{-1}$ whereas that of $C - F$ in $CF_4$ is $515\, kJ\, mol^{-1}.$ The correct reason for higher $B- F$ bond dissociation energy as compared to that of $C-F$ is
- [AIEEE 2008]
Aluminium chloride exists as dimer, $A{l_2}C{l_6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
Aluminium chloride exists as dimer, $A{l_2}C{l_6}$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
- [AIEEE 2004]